ACT2022题目及答案.doc

ACT2022题目及答案ACT20题目及答案ACT20题目及答案 全称"Ameran College Testing"，中文名称为"美国大学入学考试"， 是美国大学本科的入学条件之一，也是奖学金发放的重要根据之一由ACT INC 主办下面是WTT为你们准备的关于ACT的20年阅读以及相关答案，希望能帮 助你们 ACT题目及答案 Question #1: A rectangle is four times as long as it is wide.If the total area of the rectangle is 16 square inches, what is the length of the rectangle (a) 2 inches (b) 4 inches (c) 6 inches (d) 8 inches (e) 16 inches Solution: If is the width of the rectangle, the length is 4.The area of the rectangle is ·4 = 42.42 = 16 and = 2 inches.The length of the rectangle is 4 = 8 inches.Question #2: What is f(f(2)) if f = 2 + 2 (a) 12 (b) 26 (c) 38 (d) 42 (e) 48 Answer: f(2) = 22 + 2 = 6.f(f(2)) = f(6) = 62 + 2 = 38.Question #3: Whh of the follog is a factored form of the epression 62 + - 2 (a) (3 + 2)(2 - 1) (b) (2 + 2)(3 - 1) (c) (3 + 2)(2 + 1) (d) (3 - 2)(2 - 1) (e) (2 + 2)(3 - 2) Answer: 62 + - 2 = 62 + 4 - 3 - 2 = 2(3 + 2) - (3 + 2) = (3 + 2)(2 - 1).Question #4: In the figure below, quadrilateral ABCD has AB parallel with CD.What is the area of triangle ABD (a) 3 (b) 4 (c) 6 (d) 8 (e) 9 The area of triangle ABD is equal to (1/2)AB·DE, where DE is the altitude from D to AB.AreaABD = (1/2)4·3 = 6.Question #5: The radius of circle O is half the length of a side of square S.Column AColumn B Area of circle OArea of square S (a) The quantity in Column A is greater then the quantity in Column B.(b) The quantity in Column B is greater then the quantity in Column A.(c) The two quantities are equal.(d) The relationship cannot be determined from the information ven.Answer: The radius of circle is half the length of a side of the square, r = l/2.The area of the circle will be ·r2 The area of the square will be l2 = (2·r)2 = 4·r2 4 because = apro.3.14, so the quantity in Column B is greater then the quantity in Column A.Another simple way to solve this problem is to realize that a circle with the radius equal to half the length of a square could be inscribed in the square.Question #6: If 2 - n - 32 = 0 when = 4, what is the value of n (a) -4 (b) 4 (c) 6 (d) -2 (e) 10 Answer: We substitute = 4 in 2 - n - 32 = 0.42 - n·4 - 32 = 0.16 - 4n - 32 = 0.n = -4.Question #7: If f = || and g = 2, how many solutions has f = g (a) 1 (b) 2 (c) 3 (d) 4 (e) 5Answer: The simplest way to solve this problem is to draw the 2 functions in the , y plane.We find that the 2 functions intersect each other in 3 locations, at = -1, 0 and 1.Question #8: ven the list of integers: -2, 2, 0, 6, 8, 0, -5, 9, 10, 4, whh of the follog statements is true (a) mode median average (b) median mode average (c) median average mode (d) mode = median average (e) average median mode Answer: We need to rearrange the list of integers in ascending order: -5, -2, 0, 0, 2, 4, 6, 8, 9, 10.The average will be the sum of all integers divided by the number of integers, 32/10 = 3.2.The median will be the mean of the two middle numbers, 2 and 4, so the median is 3.The mode is 0, as 0 occurs the most in the list.The correct answer is mode median average.Question #9: A vehle runs from town A to town B at a speed of 20 miles/hour while another vehle runs from town B to town A at a speed of 60 miles/hour.Both vehles start their trips at the same time and the distance between towns is 100 miles.How long does it take from the time they start running to the moment they are at the same point on the road (a) 1 hour (b) 1 hour and 15 minutes (c) 1 hour and 30 minutes (d) 1 hour and 45 minutes (e) 2 hours and 15 minutesAnswer: 100 miles = d1 + d2 This is equation #1.It take the same time for the 2 cars to meet: t = d1/(20 miles/hour) = d2/(60miles/hour).This is equation #2.We solve the system of 2 equations to find d1 and d2.From equation #2, 3·d1 = d2.Then 100 miles = d1 + d2 = 4·d1, so d1 = 25 miles and d2 = 75 miles.The answer is t = d1/20miles/hour = 25/20 = 5/4 = 1 hour and 15 minutes.Question #10: If + 4y = 6 and - 2y = 3, whh of the follog statements is not true (a) y = 1/2 (b) = 4 (c) y = 2 (d) y = 2 (e) + y = 9/2 Answer: In order to find the values of and y, we multiply the second equation by 2 and add the 2 equations: + 4y = 6 2 - 4y = 3 3 = 12 and = 4, y = (6 - 3)/4 = 1/2.y = 2 is the only equality that is false.第 页 共 页。