C语言上机练习题(共11页).doc
11页
精选优质文档-----倾情为你奉上1. 输入一个不超过五位的正整数，输出其逆数例如输入12345，输出应为54321include "stdio.h"main(){ long n; int ww,qw,bw,sw,gw; printf("Please input:\n"); scanf("%ld",&n); while(n<=0||n>99999) { printf("\nThe number is too little or too large.Retry please!\n"); scanf("%ld",&n); } if(n>=10000&&n<=99999) { ww=n/10000; qw=n/1000%10; bw=n/100%10; sw=n/10%10; gw=n%10; printf("The old number is:%ld\n",n); printf("The new number is:%d%d%d%d%d\n",gw,sw,bw,qw,ww); } else if(n>=1000&&n<=9999) { qw=n/1000; bw=n/100%10; sw=n/10%10; gw=n%10; printf("The old number is:%ld\n",n); printf("The new number is:%d%d%d%d\n",gw,sw,bw,qw); } else if(n>=100&&n<=999) { bw=n/100; sw=n/10%10; gw=n%10; printf("The old number is:%ld\n",n); printf("The new number is:%d%d%d\n",gw,sw,bw); } else if(n>=10&&n<=99) { sw=n/10; gw=n%10; printf("The old number is:%ld\n",n); printf("The new number is:%d%d\n",gw,sw); } else printf("The old number equals the new number:%ld",n); }2. 计算1+2+3…+n的值，n是从键盘输入的自然数。
/* Note:Your choice is C IDE */#include "stdio.h"main(){ int n,i; long sum=0; printf("1+2+3+....+n\n"); printf("Please input n:\n"); scanf("%d",&n); for(i=1;i<=n;i++) { sum+=i;} printf("sum=%ld",sum); }3. 从终端（键盘）读入20个数据到数组中，统计其中正数的个数，并计算这些正数之和/* Note:Your choice is C IDE */#include "stdio.h"#define N 20main(){ int a[N],i,sum=0,count=0; printf("Please input numbers :\n"); for(i=0;i
/* Note:Your choice is C IDE */#include "stdio.h"#define N 5main(){ int a[N],b[N],i; printf("Please input numbers:\n"); for(i=0;i 例如若n为1000时，函数值应为：s=153.909064/* Note:Your choice is C IDE */#include "stdio.h"#include "math.h"main(){ int n,s,i; float sum=0; printf("Please input n:\n"); scanf("%d",&n); while(n<=0) { printf("\nError input.Retry please:\n"); scanf("%d",&n); } for(i=1;i /* Note:Your choice is C IDE */#include "stdio.h"main(){ int n; printf("Please input n:\n"); scanf("%d",&n); while(n<1||n>10) { printf("Error input!Retry please:\n"); scanf("%d",&n); } switch(n) { case 1:printf("One!");break; case 2:printf("Two!");break; case 3:printf("Three!");break; case 4:printf("Four!");break; case 5:printf("Five!");break; case 6:printf("Six!");break; case 7:printf("Seven!");break; case 8:printf("Eight!");break; case 9:printf("Nine!");break; case 10:printf("Ten!");break; } }9. 个位数为6且能被3整除但不能被5整除的三位自然数共有多少个，分别是哪些？/* Note:Your choice is C IDE */#include "stdio.h"main(){ int i,count=0; for(i=106;i<596;i=i+10) { if(i%3==0&&i%5!=0) { printf("%-4d",i); count++; } } printf("count=%-4d",count);}10. 用自然语言描述程序逻辑如下，试写程序。 ① 设置环境；② 定义变量i、j、s，以及用于放置结果的变量sum，并令sum初值为0；③ i=1；④ 如果i≤100，则转⑤，否则转⑧；⑤ 令s=0，求前i个自然数之和，并放于变量s之中；⑥ sum=sum+s；⑦ i增加1，转④；⑧ 输出和sum，结束/* Note:Your choice is C IDE */#include "stdio.h"main(){ int i,j; long s=0,sum=0; printf("1+1+2+1+2+3+1+2+3+4+....1+2+3+..+n\n"); i=1; while(i<=3) { s+=i; sum+=s; i++; } printf("sum=%ld",sum);}11. 用自然语言描述的程序逻辑为：① 设置环境；② 定义变量i、flag和password，并令flag=0，i=0；③ 用户回答。
