合工大matlab实验报告.doc

1．自确定．自确定 2 个传递函数，实现传递函数的录入和求取串联、个传递函数，实现传递函数的录入和求取串联、并联、反馈连接时等效的并联、反馈连接时等效的整体整体传递函数要求分别采用有理多传递函数要求分别采用有理多项式模型和零极点增益模型两种传递函数形式项式模型和零极点增益模型两种传递函数形式有理多项式模型有理多项式模型num=[10,18,3]; den=[8,5,0,7]; sys=tf(num,den)Transfer function: 10 s^2 + 18 s + 3 ----------------- 8 s^3 + 5 s^2 + 7num=[16,0,8,3]; den=[6,4,14,8,0]; sys=tf(num,den)Transfer function:16 s^3 + 8 s + 3 ---------------------------- 6 s^4 + 4 s^3 + 14 s^2 + 8 sn1=[10 18 3];d1=[8 5 0 7];n2=[16 0 8 3];d2=[6 4 14 8 0];G1=tf(n1,d1); G2=tf(n2,d2);G=series(G1,G2)Transfer function: 10 s^2 + 18 s + 3 ----------------- 8 s^3 + 5 s^2 + 7n1=[10 18 3];d1=[8 5 0 7];n2=[16 0 8 3];d2=[6 4 14 8 0];G1=tf(n1,d1); G2=tf(n2,d2);G1+G2Transfer function: 188 s^6 + 228 s^5 + 294 s^4 + 520 s^3 + 201 s^2 + 80 s + 21 ------------------------------------------------------------ 48 s^7 + 62 s^6 + 132 s^5 + 176 s^4 + 68 s^3 + 98 s^2 + 56 s>> n1=[10 18 3];d1=[8 5 0 7];n2=[16 0 8 3];d2=[6 4 14 8 0];G1=tf(n1,d1);G2=tf(n2,d2);G=feedback(G1,G2,1)Transfer function:60 s^6 + 148 s^5 + 230 s^4 + 344 s^3 + 186 s^2 + 24 s ---------------------------------------------------------------48 s^7 + 62 s^6 - 28 s^5 - 112 s^4 - 60 s^3 - 76 s^2 - 22 s - 9零极点增益模型零极点增益模型>> z=[-5]; p=[3,5,9]; k=8; sys=zpk(z,p,k)Zero/pole/gain:8 (s+5) ----------------- (s-3) (s-5) (s-9)>> z=[8];p=[5,12,4];k=12; >> sys=zpk(z,p,k)Zero/pole/gain:8 (s+5) ----------------- (s-3) (s-5) (s-9)>> z=[-5]; p=[3,5,9]; k=8;G1=zpk(z,p,k);z1=[8];p1=[5,12,4];k1=12;G1=zpk(z,p,k); G2=zpk(z1,p1,k1);G=G1*G2Zero/pole/gain:96 (s+5) (s-8) -------------------------------- (s-3) (s-4) (s-5)^2 (s-9) (s-12)>> z=[-5]; p=[3,5,9]; k=8;G1=zpk(z,p,k);z1=[8];p1=[5,12,4];k1=12;G1=zpk(z,p,k); G2=zpk(z1,p1,k1);G1+G2Zero/pole/gain: 20 (s-11.24) (s-5) (s-4.497) (s-0.6648) ---------------------------------------(s-3) (s-4) (s-5)^2 (s-9) (s-12)>> z=[-5]; p=[3,5,9]; k=8;G1=zpk(z,p,k);z1=[8];p1=[5,12,4];k1=12;G1=zpk(z,p,k); G2=zpk(z1,p1,k1);G=feedback(G1,G2,-1)Zero/pole/gain:8 (s+5) (s-5) (s-4) (s-12) ----------------------------------------------------------------- (s-1.438) (s-7.455) (s^2 - 21.48s + 115.6) (s^2 - 7.624s + 23.05)2 2．进行．进行 2 2 例有理多项式模型和零极点增益模型间的转换例有理多项式模型和零极点增益模型间的转换num=[6,9]; den=[3,8,0]; sys=tf(num,den);[z,p,k]=tf2zp(num,den)z =-1.5000p =0-2.6667k =2z=[-3]; p=[-1,-2,-5]; k=6; sys=zpk(z,p,k);[num,den]=zp2tf(z,p,k)num =0 0 6 18den =1 8 17 103 3．．在在 Siumlink 环境下实现如下系统的环境下实现如下系统的传递函数的求取。

传递函数的求取各环节传递函数自定各环节传递函数自定[n,d]=linmod('uu') n =0 0 0 -2.0000 10.0000 -0.0000 -0.0000d =1.0000 2.6667 -13.6667 -17.6667 36.6667 15.0000 0.00004 4．用画．用画信号流程图方法信号流程图方法求取下面系统的传递函数求取下面系统的传递函数[n,d]=linmod('untitled') n =1.0e+003 *Columns 1 through 70 0 0 0 -0.0768 1.2288 -4.6080Column 80d =1.0e+003 *Columns 1 through 70.0010 0.0117 -0.0235 -0.2439 0.2829 -1.0939 -9.0880Column 80。