电磁兼容导论第9章、第10章部分答案及解析.doc

9.4.10 Repeat Problem 9.4.8 for the ribbon cable of Problem 9.4.3 where RS=RL=RNE=RFE=63.25Ω. [VNE,max=0.791,VFE,max=0]解：为1MHz,5V,占空比50%,上升/下降时间为50ns远近端串扰系数：此脉冲串的"摆动速率"为：近端远端9.4.11 Repeat Problem 9.4.8 for the problem of two wires over a ground plane of problem 9.4.4.[VNE,max=10.7mV,VFE,max=2.67mV]解：导线上总电感总电容远端和近端串扰系数此脉冲串的"摆动速率"为：近端远端9.7.2 For the line in Problem 9.7.1, determine the frequency where the shield will affect the inductive coupling when it is grounded at both ends.[970 Hz]解： 设导线长为拐点频率即所求频率为9.7.3 If the shield in Problem 9.7.1 is grounded at both ends, the line length is 2m and RS=0, RL=1KΩ, RNE=100Ω, and RFE=50Ω determine the near-end crosstalk transfer ratio at 100 Hz, 1 KHz, 100 KHz, and 10 MHz.[0.38 x 10-6,2.67 x 10-6, 3.72 x 10-6, 3.72 x 10-6]解：因为两端接地,所以容性耦合为0拐点频率 所求为所求为：当时,感性耦合和频率的变化无关,所以时,所求值不在变化,均为9.7.4 For the ribbon cable shown in Fig. P9.3.4 assume the total mutual inductance and mutual capacitance to be LM=0.4μH and Cm=400pF. If VSt is a 1 MHz sinusoid of magnitude 1 V, and the termination impedances are RS=RL=RNE=RFE=50Ω, determine the near-end crosstalk if a shield is placed around the receptor wire and the shield is only connected to the near end of the reference wire. [12.57mV] How much does the shield reduce the crosstalk? [10.88dB]解：因为接收导线和参考导线近端相连,故容性融合为0感性融合系数：此脉冲串的"摆动速率"为：则屏蔽层能减少干扰10.2.4 Compute the reflection loss and absorption loss for a 20 mil steel barrier at 30 MHz, 100 MHz, and 1 GHz, assuming a far-fieldsource. [53.23 dB, 3656.6 dB, 48 dB, 6676.0 dB, 38 dB, 21,111 dB]解：时,反射损耗和吸收损耗分别为：时,反射损耗和吸收损耗分别为：时,反射损耗和吸收损耗分别为：10.3.1 Compute the reflection loss and absorption loss for a 20-mil steel barrier at 10 kHz, 100 kHz, and 1 MHz for a near-field electricsource that is a distance of 5 cm from the shield. [188.02 dB, 66.76 dB,158.02 dB, 211.11 dB, 128.02 dB, 667.6 dB]解：近电场情况下时,反射损耗和吸收损耗分别为：时,反射损耗和吸收损耗分别为：时,反射损耗和吸收损耗分别为：10.3.2 Compute the reflection loss and absorption loss for a 20-mil steel barrier at 10 kHz, 100 kHz, and 1 MHz for a near-fieldmagnetic source that is a distance of 5 cm from theshield. [211.45 dBuse R = 0, 66.76 dB, 21.45 dB use R =0, 211.11 dB, 8.55 dB, 667.6 dB]解：近磁场情况下时,反射损耗和吸收损耗分别为：时,反射损耗和吸收损耗分别为：时,反射损耗和吸收损耗分别为：.。