高层临时用电工程施工组织设计方案培训资料全.doc

. . 高层临时用电施工方案培训资料----------------------- -----------------------日期： / 北城丽都（14、15、19号楼）工程施工临时用电专项方案 审批：市和霖建筑工程XX公司2010年12月北城丽都（14、15、19号楼）工程施工临时用电专项方案 北城丽都（14、15、19号楼）工程工程；属于框架结构;地上26层;地下1层；建筑高度：89.5m；标准层层高：3.00m；总建筑面积：49999.2平方米；总工期：1000天该工程临时用电布置，主要考虑主体阶段，基础阶段的施工，考虑在备用开关上另外设立干线解决，基础阶段的布置从略一、编制依据《低压配电设计规》GB50054-95《建筑工程施工现场供电安全规》GB50194-93《通用用电设备配电设计规》GB50055-93《供配电系统设计规》GB50052-95《施工现场临时用电安全技术规》JGJ46-2005《建筑施工安全检查标准》JGJ59-99二、主体施工阶段用电计算（一）、施工条件施工现场用电量统计表:------------------------------------------------------------序号机具名称型号安装功率(kW) 数量合计功率(kW)1 塔式起重机 QT40 48 31442 钢筋调直机 GT4/14 4 3123 钢筋切断机 QJ40 7 3 214插入式振动器 ZX50 1.1 6 6.65交流电焊机 BX3-500-2 38.6 3 115.86木工圆锯 MJ104 3 5157载货电梯 JT1 7.5 322.5-------------------------------------------------------------（二）、设计容和步骤1、现场勘探与初步设计:(1)本工程所在施工现场围无各种埋地管线。

2)现场采用380V低压供电，设一配电总箱，4条干线，其中1号干线供应A-1、2栋，2号干线供应A-3、4栋，3号干线供应A-5、6栋，4号干线供应A-7栋，1、2、3号干线各配置两个分电箱，采用TN-S系统供电3)根据施工现场用电设备布置情况，采用导线穿钢管埋地敷设，布置位置与线路走向参见临时配电系统图与现场平面图，采用三级配电，两级防护4)按照《JGJ46-2005》规定制定施工组织设计，接地电阻R≤4Ω2、确定用电负荷:Pn—安装功率 Pe—额定功率 Pjs—有功功率 Qjs—无功功率 Sjs—视在功率 1号干线（14、15号楼）(1)、塔式起重机Kx = 0.2 Cosφ = 0.6 tgφ = 1.33将Jc =40%统一换算到Jc1 =25%的额定容量Pn = 48kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.4/0.25)1/2×48 = 60.72 kWPjs = Kx×Pe =0.2×60.72 = 12.14kWQjs = Pjs× tgφ=12.14×1.33 = 16.19 kvar(2)、钢筋调直机Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×4 = 1.2 kWQjs = Pjs× tgφ=1.2×1.02 = 1.22 kvar(3)、钢筋切断机Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×7 = 2.1 kWQjs = Pjs× tgφ=2.1×1.02 = 2.14 kvar(4)、强制式混凝土搅拌机Kx = 0.75 Cosφ = 0.85 tgφ = 0.62Pjs = 0.75×11 = 8.25 kWQjs = Pjs× tgφ=8.25×0.62 = 5.11 kvar(5)、插入式振动器Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×2.2 = 0.66 kWQjs = Pjs× tgφ=0.66×1.02 = 0.67 kvar(6)、交流电焊机Kx = 0.35 Cosφ = 0.4 tgφ = 2.29将Jc =50%统一换算到Jc1 =100%的额定容量Pn = Sn×Cosφ = 38.6×0.4=15.44kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×15.44 = 10.92 kWPjs = Kx×Pe =0.35×10.92 = 3.82kWQjs = Pjs× tgφ=3.82×2.29 = 8.76 kvar(7)、木工圆锯Kx = 0.3 Cosφ = 0.6 tgφ = 1.33Pjs = 0.3×3 = 0.9 kWQjs = Pjs× tgφ=0.9×1.33 = 1.2 kvar(8)、载货电梯Kx = 0.2 Cosφ = 0.6 tgφ = 1.33Pjs = 0.2×7.5 = 1.5 kWQjs = Pjs× tgφ=1.5×1.33 = 2 kvar(9)、塔式起重机Kx = 0.2 Cosφ = 0.6 tgφ = 1.33将Jc =40%统一换算到Jc1 =25%的额定容量Pn = 48kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.4/0.25)1/2×48 = 60.72 kWPjs = Kx×Pe =0.2×60.72 = 12.14kWQjs = Pjs× tgφ=12.14×1.33 = 16.19 kvar(10)、强制式混凝土搅拌机Kx = 0.75 Cosφ = 0.85 tgφ = 0.62Pjs = 0.75×11 = 8.25 kWQjs = Pjs× tgφ=8.25×0.62 = 5.11 kvar(11)、插入式振动器Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tgφ=0.33×1.02 = 0.34 kvar(12)、载货电梯Kx = 0.2 Cosφ = 0.6 tgφ = 1.33Pjs = 0.2×7.5 = 1.5 kWQjs = Pjs× tgφ=1.5×1.33 = 2 kvar(13)、交流电焊机Kx = 0.35 Cosφ = 0.4 tgφ = 2.29将Jc =50%统一换算到Jc1 =100%的额定容量Pn = Sn×Cosφ = 23.4×0.4=9.36kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×9.36 = 6.62 kWPjs = Kx×Pe =0.35×6.62 = 2.32kWQjs = Pjs× tgφ=2.32×2.29 = 5.31 kvar2号干线（19号楼）(1)、塔式起重机Kx = 0.2 Cosφ = 0.6 tgφ = 1.33将Jc =40%统一换算到Jc1 =25%的额定容量Pn = 48kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.4/0.25)1/2×48 = 60.72 kWPjs = Kx×Pe =0.2×60.72 = 12.14kWQjs = Pjs× tgφ=12.14×1.33 = 16.19 kvar(2)、强制式混凝土搅拌机Kx = 0.75 Cosφ = 0.85 tgφ = 0.62Pjs = 0.75×11 = 8.25 kWQjs = Pjs× tgφ=8.25×0.62 = 5.11 kvar(3)、插入式振动器Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×2.2 = 0.66 kWQjs = Pjs× tgφ=0.66×1.02 = 0.67 kvar(4)、钢筋调直机Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×4 = 1.2 kWQjs = Pjs× tgφ=1.2×1.02 = 1.22 kvar(5)、钢筋切断机Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×7 = 2.1 kWQjs = Pjs× tgφ=2.1×1.02 = 2.14 kvar(6)、钢筋弯曲机Kx = 0.3 Cosφ = 0.7 tgφ = 1.02Pjs = 0.3×3 = 0.9 kWQjs = Pjs× tgφ=0.9×1.02 = 0.92 kvar(7)、交流电焊机Kx = 0.35 Cosφ = 0.4 tgφ = 2.29将Jc=50%统一换算到Jc1 =100%的额定容量Pn = Sn×Cosφ = 23.4×0.4=9.36kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×9.36 = 6.62 kWPjs = Kx×Pe =0.35×6.62 = 2.32kWQjs = Pjs× tgφ=2.32×2.29 = 5.31 kvar(8)、木工圆锯Kx = 0.3 Cosφ = 0.6 tgφ = 1.33Pjs = 0.3×3 = 0.9 kWQjs = Pjs× tgφ=0.9×1.33 = 1.2 kvar(9)、载货电梯Kx = 0.2 Cosφ = 0.6 tgφ = 1.33Pjs = 0.2×7.5 = 1.5 kWQjs = Pjs× tgφ=1.5×1.33 = 2 kvar1、2号干线线路上导线截面与分配箱、开关箱电气设备选择:在选择前应对照平面图和系统图先由用电设备至开关箱计算，再由开关箱至分配箱计算，选择导线与开关设备。

分配箱至开关箱，开关箱至用电设备的导线敷设采用铜塑料绝缘导线穿焊接钢管敷设，由于这部分距离较短，因此不考虑电压降，只按安全载流量选择导线截面1)、塔式起重机开关箱至塔式起重机导线截面与开关箱电气设备选择（开关箱以下机械启动后需要系数取1）:i)计算电流Kx = 1 Cosφ = 0.6 tgφ = 1.33Ijs = Kx×Pe /(1.732×Ue×Cosφ) = 1×60.72/(1.732×0.38×0.6) = 153.75Aii)选择导线选择BV-4×70+1×35 ，穿焊接钢管时其安全载流量为183Aiii)选择电气设备选择开关箱开关为DZ10-250/3 ，其脱扣器整定电流值为Ir = 200A漏电保护器为 DZ10L-250/32)、钢筋调直机开关箱至钢筋调直机导线截面与开关箱电气设备选择（开关箱以下机械启动后需要系数取1）:i)计算电流Kx = 。