非对称喷嘴挡板式电液伺服阀特性分析.pdf

dë¨I“ðTÈAº›D+Ÿs訚耀保 孟 伟同济大学,上海,200092K1:分析了一种新型非对称喷嘴挡板式电液伺服阀的结构和特性b该阀在两喷嘴容腔处设置一对阻尼节流器,得到了喷嘴容腔和负载压力特性a零位压力特性,以及力矩马达驱动力和刚度设计方法b理论和试验结果表明:内置阻尼节流器的电液伺服阀喷嘴容腔的零位压力小于供油压力的50%,负载容腔的零位压力大于供油压力的50%;液阻系数不对称时,负载压力曲线不对称,其交点偏离中位;为提高零位时负载压力的线性度,液阻系数的取值宜在115至215之间b1oM:dë¨I“ð;ÈAº›D;«@;¸8;â ï+ŸÏms Ë|:TH137.5 ÓcI|:1004 ) 132X(2011)08) 0957) 04Characteristics of Electro- hydraulic Servovalve with an AsymmetricNozzle FlapperYin Yaobao Meng WeiTongjiUniversity,Shanghai,200092Abstract:Thestructureand characteristics of an electro hydraulicservovalvewith an asymmetricnozzle flapper whichhasapair of hydraulicresistancesin thenozzlechamberswereanalyzed. Theloadpressurecharacteristics, nozzle chamber pressure characteristics and the pressure characteristics atzero point wereobtained. Thedesignmethodofforceandrigidityof thetorquemotor werediscussed.Thetheoretical results arein good agreement with theexperimental ones.Theload pressureof electrohydraulicservovalvewith an asymmetric nozzle flapper at zero point is bigger than 50% of supplypressure, but the nozzle chamber pressure is less than 50% of supply pressure. The load pressurecharacteristicsareasymmetric, andthecrosspoint of thetwoload pressurecurvesdeviates theneutralpoint.Thecoefficient ofhydraulicresistanceis suggestedtobe1.5to2.5inorder togetgood linearityof load pressure.Key words:asymmetric nozzle flapper;electro hydraulicservovalve;resistance;chamber;pressurecharacteristicslà°ù:2010) 06) 18Á[":SE1– SÐÁ'ù["(50775161);t b SÐÁ'ù["(20090738003);SEÚ/Œùî?Z9Ã(8639Ã)'ù["(2007AA05Z119)0 引言20W@50M},Moog?üW¸»Bû¨I“ðT)ÈAº›D[1-2]bª,ÈAº›D$ï„‹¨¿fù ï :"d[#òñý 015;AE"”1v,wLM,â ïØ«S¶Ml;’ñED«@ d‚ë,'A b1 X A b2H,ÂwL4„wL5îUµ¸8¥â ï+Ÿ‚ë,O,ÊH, p 10/ p s X p20/ psbƒÕdë¨I“ðTÈAº›D V¨¿Aâ ï eÅ"d„dëAâÒ¥µÄ¥ eÅb1. kb1 = 0 2. kb2 = 0 3. kb1 = 1 4. kb2 = 15. kb1 = 2 6. kb2 = 2 7. kb1 = 3 8. kb2 = 3m4 ñµ¸8=¥áÿâ ï+Ÿ®m3 V©,{ED«@¥¨I“ðÈAº›D¥ñ¨I¸8â ïMÄS¶vb®m4 V©,ñµ¸8¥µâ ïMÄS¶lbÐôYÈAº›DM1,{ED«@¥ÈAº›D¥¨I¸8â ïMÄS¶v,'È|¥ eÅS¶v,¨I“ðD¥ eÅÚÚ,Aâ?÷ æ¨rqÚb’‚{ED«@¥¨I“ðÈAº›D¨I)?3
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Ö(Ab1 X Ab2)f ƒ/¨I¸8â ï+Ÿ„µâ ï+ŸbA⺛"dÏ,¨I“ðDBîýT,ʸÍ,OÈÈ1pµ g¥â ïMÄVñÜ×b¹s¨I“ðD,ÊHµâ ïwL¥LŸ,ƒ Ú„ƔÐÏ¥wqÀQb¹PµâïwLMÄÜÏ,wqlzb®T(6) ~T(9) V¤,Ê(xf/ xf0 = 0)Hµâ ïwLp1/ psap2/ ps¥wq:K1 = 4( k2b1 + 1) + 6 (k2b1 + 1) 2 - 2( k2b1 + 2)4[ 1+ 4(2+ k2b1)4]32(11)K2 = 4( k2b2 + 1) + 6 (k2b2 + 1) 2 - 2( k2b2 + 2)4 [ 1+ 4(2+ k2b2)4]32(12)®T(11)„T(12) V[¤ž,ÊHµâïwL¥wq„AE"”¥1"wL,Âm5îUb Vn,HwL›†BÁbAE"”¹0.6H,wqrž‚´0139b¹4Ú,ÊHµâ ïwL¥LŸ,ýTÄBî‹ÐEçwq‚´¸Í¥u×b InžL=â ï eÅS¶,wq´‹ûa’S¶=,ypAE"”Ê41. 5À2.5­Wbm5 ,ÊHµâ ïwL¥wq+Ÿ2.1. 2 ,Êâ ï+Ÿ!xf = 0,®T(6) ~T(10) V¤¨I“ðTÈAº›D,ÊHò¸8¥â ï9ØT:pc10= p s2+ k2b1(13)pc20= p s2+ k2b2(14)p10 = 1+ k2b12+ k2b1 ps (15)p20 = 1+ k2b22+ k2b2 ps (16)m6îU¹¨I¸8„µ¸8¥,Êâ ï+ŸwLb Vn,,Êâ ïÛ¨IAE"”¥MÄ7MÄ,AE"”¹,H,µâ ï¹²â ï¥50%,'pc10/ p s = p10 / ps = 015, pc20/ ps =p20/ ps = 015;AE"”v,¨I¸8¥,Êâï®,µ¸8¥,Êâ ïÚ,Opc10/ p s = p10/ p s 015b2. 2 “ð¥zî ï“ðî³1¥zî ïvl %ç ï ”r!9¥'•”,¹Ns“ðzî ï¥9ØZEbæ¨um æZñ[2] V¤ž¨I1)¥@8T¨¿“ð¥ ï:F1 = (pc1+ Qv21/2) AN (17)v1 = qm2AN= CdfPDN1(x f0 - xf) 2pc1/QPD2N/ 4=#959#dë¨I“ðTÈAº›D+Ÿs)) ) 訚耀保 孟 伟1.¨I¸8â ï1 2.µ¸8â ï1m6 ,Êâ ï+Ÿ4Cdf( xf0 - x f) 2pc1/QDN (18)TÏ, v1¹@8¨I d g)¥Î; AN¹¨I dëb®T(17)aT(18) V¤F1 = pc1A N + 4PC2df ( xf0 - xf)2pc1 (19)] Ø V¤¨I2)¥@8T¨¿“ð¥ ï:F2 = pc2A N + 4PC2df ( xf0 + xf)2pc2 (20)®T(19)aT(20)„T(7)aT(9) , V¤“ð¥zî ï:F1 - F2 = (pc1- pc2) AN + 4PC2dfx2f0( pc1- pc2) +4PC2dfx2f ( pc1- pc2) - 8K psPC2dfxf0psxf (21)K ps = [1+ (k2b1 + 1) (1- x)2] -1 +[1+ (k2b2 + 1) (1- x)2] -1 (22)TÏ, K ps¹×ÿâ ïyQ´,Oµx = xf/ xf0b¨I“ðDÏ ëÊÂH, x = 0,µK ps = (2+ k2b1)- 1+ (2+ k2b2)- 1 (23)VT(23) V[ A,¨I“ðD×ÿâ ïyQ´K ps rbyN,‹Ðhlõ Ë8à_M™–[üÉõ Ë8¥P¨p
b• IÓD:[1] TÊ nshoff H K,Scherger A.About Damping Mecha-nisms for Disk Shaped Tools[ J]. CIRP Annals,Manufacturing Technology,1981,30(1):305-309.[2] …½T,Nl. Ë‹ ïsƒÐ>rs[J].µ2ÓØÐýÐ(1– SÐñ),2007,19(2):59-62.[3] Tian J,Hutton S G.Cutting- induce。